Respuesta :

5 and 6  and 3 and 10, the pairs of numbers that have a least common multiple of 30.

Step-by-step explanation:

Case 1: LCM (3, 6)

Prime factorization of 3:  [tex]1 \times 3[/tex]

Prime factorization of 6:  [tex]2 \times 3[/tex]

Using all prime numbers found as often as each occurs most often we take

               [tex]2 \times 3=6[/tex]

Therefore LCM (3, 6) = 6.

Case 2: LCM (5, 6)

Prime factorization of 5:  [tex]1 \times 5[/tex]

Prime factorization of 6:  [tex]2 \times 3[/tex]

Using all prime numbers found as often as each occurs most often we take

                     [tex]5 \times 2 \times 3=30[/tex]

Therefore LCM (5, 6) = 30

Case 3: LCM (3, 10)

Prime factorization of 3:  [tex]1 \times 3[/tex]

Prime factorization of 10:  [tex]2 \times 5[/tex]

Using all prime numbers found as often as each occurs most often we take

                    [tex]5 \times 2 \times 3=30[/tex]

Therefore LCM (3, 10) = 30

Case 4: LCM (5, 10)

Prime factorization of 5:  [tex]1 \times 5[/tex]

Prime factorization of 10: [tex]2 \times 5[/tex]

Using all prime numbers found as often as each occurs most often we take

                       [tex]5 \times 2=10[/tex]

Therefore LCM (5, 10) = 10

Answer:

10=ten

Step-by-step explanation:

i took the test and got a complete A+