Answer:
534 ft
Explanation:
given,
speed of the vehicle = 60 mph
1 mph = 0.447 m/s
60 mph = 60 x 0.447 = 26.82 m/s
stopping distance = ?
Stopping distance of the car is equal to the distance traveled in the reaction time and the braking distance.
Reaction time of a common person = 1.5 s
taking coefficient of friction of the road = 0.3
using equation of stopping sight distance
S.D = RD + BD
RD is Reaction distance
RD = v t_r
RD = 26.82 x 1.5
RD = 40.23 m
BD is the braking distance
[tex]BD = \dfrac{v^2}{2\mu g}[/tex]
[tex]BD = \dfrac{26.82^2}{2\times 0.3\times 9.8}[/tex]
BD = 122.33 m
Stopping sight distance
SD = 40.23 + 122.33
SD = 162.56 m
1 m = 3.28 ft
162.56 m = 162.56 x 3.28
= 533.20 ft ≈ 534 ft
hence, the stopping distance will be equal to 534 ft
