Answer:
[tex]\frac{n_p}{n_s}=\frac{1}{1000}[/tex]
Step-by-step explanation:
Given voltage of primary coil is [tex]V_p=12V[/tex]
And voltage of secondary coil is [tex]V_s=12,000V[/tex]
A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil [tex](n_p)[/tex] and secondary coil [tex](n_s)[/tex].
Following equation represents the relation between them.
[tex]\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}[/tex]
Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is
[tex]\frac{n_p}{n_s}=\frac{1}{1000}[/tex]
