Respuesta :
Answer:
StartFraction 5 Over 4 k squared EndFraction
Step-by-step explanation:
We are asked to find the next product:
[tex] \frac{5 k}{6} \times \frac{3}{2 k^3} [/tex]
Dividing numerator and denominator by k:
[tex] \frac{5 \frac{k}{k}}{6} \times \frac{3}{2 \frac{k^3}{k}} [/tex]
[tex] \frac{5}{6} \times \frac{3}{2 k^2} [/tex]
Dividing numerator and denominator by 3:
[tex] \frac{5}{\frac{6}{3}} \times \frac{\frac{3}{3}}{2 k^2} [/tex]
[tex] \frac{5}{2} \times \frac{1}{2 k^2} = \frac{5}{4 k^2} [/tex]
