Which equation represents a circle that contains the point (-5, -3) and has a center at (-2, 1)?
Distance formula: Vx2 - )2 + (y2 -
?
(x - 1)2 + (y + 2)2 = 25
o (x + 2)2 + (y - 1)2 = 5
. (x + 2)2 + (y - 1)2 = 25
(x - 1)2 + (y + 2)2 = 5

Respuesta :

The correct answer is: (x + 2)^2 + (y - 1)^2 = 25

Step-by-step explanation:

Given

Point on circle = P = (-5,-3)

Centre = C = (-2,1)

The distance between C and P is the radius of circle.

So,

[tex]CP = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\= \sqrt{(-5+2)^2+(-3-1)^2}\\=\sqrt{(-3)^2+(-4)^2}\\= \sqrt{9+16}\\=\sqrt{25}\\=5\ units[/tex]

Hence,

r = 5 units

The general form of equation of circle is:

[tex](x-h)^2+(y-k)^2 = r^2[/tex]

Here (h,k) are the coordinates of circle

(h,k) = (-2,1)

Putting the values in standard equation

[tex](x-(-2))^2+(y-1)^2 = (5)^2\\(x+2)^2+(y-1)^2 = 25[/tex]

Hence,

The correct answer is: (x + 2)^2 + (y - 1)^2 = 25

Keywords: Circle, equation of circle

Learn more about equation of circle at:

  • brainly.com/question/9231234
  • brainly.com/question/9214411

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The equation of the circle will be [tex](x+2)^2+(y-1) = 25\\[/tex]

Equation of a circle

The formula for calculating the equation of a circle is expressed as:

(x-a)^2+ (y-b)^2=  r^2

where:

(a, b) is the center = (-2, 1)

r is the radius

Find the radius

[tex]r=\sqrt{(-3-1)^2+(-5+2)^2} \\r=\sqrt{(-4)^2+(-3)^2}\\ r= \sqrt{16+9}\\ r = 5 units[/tex]

The equation of the circle will be [tex](x+2)^2+(y-1) = 25\\[/tex]

Learn more on equation of a circle here:https://brainly.com/question/1506955