1) The average velocity is 56 m/min
2) The average velocity is -83 m/min
Explanation:
1)
The average velocity of an object is given by
[tex]v=\frac{d}{t}[/tex]
where
d is the displacement (change in position)
t is the time elapsed
In the graph in the problem, the displacement corresponds to the distance, therefore to the change in the y-variable ([tex]\Delta y[/tex]), while the time elapsed is the change in the x-variable ([tex]\Delta x[/tex]), so the average velocity can be written as
[tex]v=\frac{\Delta y}{\Delta x}[/tex]
At point A, we have:
[tex]y_A = 5 m\\x_A = 0.1 min[/tex]
At point B, we have:
[tex]y_E = 55 m\\x_A = 1 min[/tex]
So, we have
[tex]\Delta y= 55 -5 = 50 m\\\Delta x = 1.0-0.1 = 0.9 min[/tex]
So the average velocity is
[tex]v=\frac{50 m}{0.9 min}=56 m/min[/tex]
2)
In this part instead, we have the following:
At point F, we have:
[tex]y_F = 55 m\\x_A = 1.3 min[/tex]
At point H, we have:
[tex]y_H = 30 m\\x_A = 1.6 min[/tex]
So, we have
[tex]\Delta y= 30 -55 = -25 m\\\Delta x = 1.6-1.3 = 0.3 min[/tex]
So the average velocity is
[tex]v=\frac{-25 m}{0.3 min}=-83 m/min[/tex]
Learn more about velocity:
brainly.com/question/8893949
brainly.com/question/5063905
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