Solving the right triangle ‼️ (Round to the nearest tenth) can someone help me find A,a, and b❓

A is 40 degrees imma edit this or do it in comments the other ones
Answer:
see explanation
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Subtract the sum of the 2 angles from 180 for A
A = 180° - (50 + 90)° = 180° - 140° = 40°
Use the cosine and sine ratios in the right triangle for a and b
cos50° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{a}{26}[/tex]
Multiply both sides by 26
26 × cos50° = a, thus
a ≈ 16.7 ( to the nearest tenth )
sin50° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{b}{26}[/tex]
Multiply both sides by 26
26 × sin50° = b, thus
b ≈ 19.9 ( to the nearest tenth )