A man starts out on a trip driving his car at a constant rate of 48 mph. A man riding a motorcycle starts out on the same route 112 hours later, traveling at a constant rate of 64 mph. How long will the car have been traveling when the motorcycle catches up?

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frika

Answer:

4.5 hours

Step-by-step explanation:

Let x hours be the time needed the motorcycle to catch the car.

Car:

Time [tex]=t+1\dfrac{1}{2}[/tex] hours

Rate = 48 mph

Distance [tex]=48\cdot \left(t+1\dfrac{1}{2}\right)[/tex] miles

Motorcycle:

Time [tex]=t[/tex] hours

Rate = 64 mph

Distance [tex]=64\cdot t[/tex] miles

The distance traveled is the same, so

[tex]48\cdot \left(t+1\dfrac{1}{2}\right)=64\cdot t\\ \\48t+72=64t\\ \\72=16t\\ \\t=4.5\ hours[/tex]

Answer:

6 hours on edge

Step-by-step explanation: