Answer:
D) -122
Step-by-step explanation:
Given:
[tex]f(x) = 2x^3-\frac{3}2x[/tex]
We need to find f(-4).
Now by substituting the value of x =-4 in above equation we get;
[tex]f(-4)= 2\times(-4)^3-\frac{3}{2}\times(-4)\\[/tex]
By using PEDMAS we will solve for exponential function first we get;
Now we know that [tex](-4)^3=-64[/tex]
So we get;
[tex]f(-4)= 2\times(-64)-\frac{3}{2}\times(-4)\\[/tex]
Now using PEDMAS we will solve division.
[tex]f(-4)= 2\times(-64)-1.5\times(-4)[/tex]
Now using PEDMAS we solve multiplication.
[tex]f(-4)= -128+6[/tex]
Finally by subtraction we get;
[tex]f(-4)= -122[/tex]
