The solution is: x=1, y=-2
Step-by-step explanation:
Given equations are:
[tex]15y-2x = -32\ \ \ Eqn\ 1\\-5y+7x = 17\ \ \ \ Eqn\ 2[/tex]
Multiplying equation 2 by 3
[tex]3(-5y+7x) = 17*3\\-15y+21x = 51\ \ \ \ Eqn\ 3[/tex]
Adding equation 1 and 3
[tex]15y-2x -15y + 21x = -32+51\\19x = 19[/tex]
Dividing both sides by 19
[tex]\frac{19x}{19} =\frac{19}{19}\\x = 1[/tex]
Putting x = 1 in equation 1
[tex]15y - 2(1) = -32\\15y -2 = -32\\15y = -32+2\\15y = -30[/tex]
Dividing both sides by 15
[tex]\frac{15y}{15} = \frac{-30}{15}\\y = -2[/tex]
Hence,
The solution is: x=1, y=-2
Keywords: Linear equation, variables
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