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How many reduced dinucleotides would be produced with four turns of the citric acid cycle?
A) 1 FAD and 4 NAD+
B) 4 FAD+ and 12 NAD+
C) 2 FADH2 and 8 NADH
D) 1 FADH2 and 4 NADH
E) 4 FADH2 and 12 NADH

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ajinems

Answer:

The reduced dinucleotides that would be produced with four turns of the citric acid cycle is E (4 FADH2 and 12 NADH)

Explanation:Each turn of the cycle forms one ATP as well as three NADH molecules and one FADH2 molecule, which will be used in further steps of cellular respiration to produce ATP for the cell. Therefore four turns of the citric acid cycle will generate 4 FADH2 and 12 NADH

batolisis

The number of reduced dinucleotides that would be produced with four turns of citric acid cycle is : ( E )  4 FADH2 and 12 NADH

Given that one ( 1 ) turn of citric acid cycle produces one ( 1 ) ATP , three ( 3 ) NADH and also produces one ( 1 ) FADH2. which are used for the production of ATP in the process of cellular respiration.

Therefore four turns of citric acid cycle will produce 4 FADH2 and  12 NADH dinucleotides.

Hence we can conclude that The number of reduced dinucleotides that would be produced with four turns of citric acid cycle is :  4 FADH2 and 12 NADH.

Learn more about citric acid cycle: https://brainly.com/question/17089080

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