Answer:
option A
Explanation:
given,
speed of car 1 = 100 Km/s
speed of car 2 = 50 Km/s
final speed = 0 Km/s
now,
skid mark when the car is moving at 100 Km/s
using equation of motion
v² = u² + 2 a s₁
0² = 100² - 2 a s₁
100² = 2 a s₁
[tex]s_1 = \dfrac{100^2}{2a}[/tex]..........(1)
now,
skid mark when the car is moving at 50 Km/s
using equation of motion
v² = u² + 2 a s₂
0² = 50² - 2 a s₂
50² = 2 a s₂
[tex]s_2 = \dfrac{50^2}{2a}[/tex]..........(2)
dividing equation (1)/ (2)
[tex]\dfrac{s_1}{s_2} = \dfrac{100^2}{50^2}[/tex]
[tex]\dfrac{s_1}{s_2} =4[/tex]
s₁ = 4 s₂
Hence, the skid mark for 100 Km/s is four time as far as 50 Km/s
The correct answer is option A
