Predict the charge on the monatomic ions formed from the following atoms in binary ionic compounds:(a) |(b) Sr(c) K(d) N(e) S(f) In

To predict the charge on a monoatomic ion we need to consider the octet rule: atoms will gain, lose or share electrons to complete their valence shell with 8 electrons.

(a) |

I has 7 valence electrons so it gains 1 electron to form I⁻ (charge 1-).

(b) Sr

Sr has 2 valence electrons so it loses 2 electrons to form Sr²⁺ (charge 2+).

(c) K

K has 1 valence electron so it loses 1 electron to form K⁺ (charge 1+).

(d) N

N has 5 valence electrons so it gains 3 electrons to form N³⁻ (charge 3-).

(e) S

S has 6 valence electrons so it gains 2 electrons to form S²⁻ (charge 2-).

(f) In

In has 3 valence electrons so it loses 3 electrons to form In³⁺ (charge 3+).

adioabiola adioabiola · Answer 2 · 2021-11-16T12:36:19+01:00

The predicted charge on the monoatomic ions formed from the following atoms in binary ionic compounds are as follows;

(a) I⁻ (charge = 1-)

(b) Sr²⁺ (charge = 2+)

(c) K⁺ (charge = 1+)

(d) N³⁻ (charge = 3-)

(e) S²⁻ (charge = 2-)

(f) In³⁺ (charge = 3+)

Basis:

The octet rule forms a basis for predicting the charge on monatomic ions formed from the following atoms in binary ionic compounds. athis is so because every atom gains or losses electrons in a bid to assume it's nearest octet configuration.

As such;

For Iodine, I

I has 7 valence electrons so it gains 1 electron to form I⁻ (charge 1-).

For Strontium, Sr

Sr has 2 valence electrons so it loses 2 electrons to form Sr²⁺ (charge 2+).

For Potassium, K

K has 1 valence electron so it loses 1 electron to form K⁺ (charge 1+).

For Nitrogen, N

N has 5 valence electrons so it gains 3 electrons to form N³⁻ (charge 3-).

For Sulphur, S

S has 6 valence electrons so it gains 2 electrons to form S²⁻ (charge 2-).

For Indium, In

In has 3 valence electrons so it loses 3 electrons to form In³⁺ (charge 3+).