Jaxon and Robert go the movie theater and purchase refreshments for their friends. Jaxon spends a total of $71.75 on 2 drinks and 9 bags of popcorn. Robert spends a total of $ 143.00 on 12 drinks and 8 bags of popcorn. Write a system of equations that can be used to find the price of one drink and the price one bag of popcorn. Using these equations, determine, and state the price of a drink, to the nearest cent.

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Answer:

The system of equations are [tex]\left \{ {{2x+9y=71.75} \atop {12x+8y=143}} \right.[/tex]

The price of one drink is $7.75 and the price one bag of popcorn is $6.25.

Step-by-step explanation:

Let the cost of 1 drink be 'x'.

And also let the cost of 1 bag of popcorn be 'y'.

Now according to question,

Jaxon spends a total of $71.75 on 2 drinks and 9 bags of popcorn.

So framing in equation form, we get;

[tex]2x+9y=71.75\ \ \ \ \ equation\ 1[/tex]

Again, Robert spends a total of $ 143.00 on 12 drinks and 8 bags of popcorn.

So framing in equation form, we get;

[tex]12x+8y=143\ \ \ \ \ equation\ 2[/tex]

Multiplying equation 1 with 6 we get;

[tex]6(2x+9y)=6\times71.75\\\\12x+54y = 430.5[/tex]

Now Subtracting equation 2 from equation 1 we get;

[tex](12x+54y) -(12x+8y) = 430.5-143\\\\12x+54y-12x-8y= 287.5\\\\46y= 287.5\\\\y=\frac{287.5}{46}= \$6.25[/tex]

Now Substituting the value of y in equation 1 we get;

[tex]2x+9y=71.75\\\\2x+9\times6.25 =71.75\\\\2x+56.25=71.75\\\\2x=71.75-56.25\\\\2x=15.5\\\\x=\frac{15.5}{2} =\$7.75[/tex]

Hence The system of equations are [tex]\left \{ {{2x+9y=71.75} \atop {12x+8y=143}} \right.[/tex]

Also The price of one drink is $7.75 and the price one bag of popcorn is $6.25.

Answer:

Step-by-step explanation: