Answer: c) 277,200
Step-by-step explanation:
The number of permutations can be formed of n things , where a things are like b things are like and so on :
[tex]\dfrac{n!}{a!\ b!....}[/tex]
The given word : ENGINEERING
Total letters = 11
Number of E's = 3
Number of N's = 3
Number of G's =2
Number of I's =2
The number of permutations can be formed from all the letters in the word "ENGINEERING" will be :
[tex]\dfrac{11!}{3!3!2!2!}\\\\=\dfrac{11\times10\times9\times8\times7\times6}{6\times6\times2\times2}\\\\=277200[/tex]
Hence, the number of permutations can be formed from all the letters in the word "ENGINEERING" = 277,200
∴ Correct answer is c) 277,200
