Answer:
We would expect 63 snails to be homozygous recessive for both traits.
Explanation:
Dihybrid cross
This is a cross between two distinct groups with different observed traits. Independent segregation is observed on the allelic pair for the genes in the separate chromosomes.
The first filial generation produces 4 similar offspring, the second filial generation, would demonstrates a phenotypic ratio of 9:3:3:1.
On dividing the 1,000 progeny on the aspect of phenotypic ratio 9:3:3:1, we can infer an approximate number of 63 (62.5) snails to be homozygous recessive for both traits.
We will calculate on the aspect of the phenotypic ratios and proportions,
Therefore
9+3+3+1 = 16.
1,000*1/16 = 62.5
62.5 can be approximated to 63
