Respuesta :
Answer:
[tex]D(t)=3 \frac{miles}{hour} +0.05*\frac{miles}{hour*F}(80F-t)[/tex]
Step-by-step explanation:
The average speed in function of the temperature:
[tex]S(t)=6 \frac{miles}{hour} +0.1*\frac{miles}{hour*F}(80F-t)[/tex]
The distance in function of the average speed:
[tex]D(x)=0.5*x[/tex]
x and S are the same
[tex]D(t)=0.5*[6 \frac{miles}{hour} +0.1*\frac{miles}{hour*F}(80F-t)][/tex]
[tex]D(t)=3 \frac{miles}{hour} +0.05*\frac{miles}{hour*F}(80F-t)[/tex]
Answer:
D(x) = 3 + 0.05*(80−t)
Step-by-step explanation:
We want to find a relation between D, distance, and t, temperature.
Distance follows the equation:
D(x) = 0.5*x
where x is average speed.
Average speed is modeled by:
S(t) = 6 + 0.1*(80−t)
Replacing x = S(t):
D(x) = 0.5*[6 + 0.1*(80−t)]
D(x) = 0.5*6 + 0.5*0.1*(80−t)
D(x) = 3 + 0.05*(80−t)