Answer:
The dimension of the rectangle
Length = 20 inches
Breadth = 18 inches
Step-by-step explanation:
Given:
The perimeter of rectangle = 76 inches
Perimeter of the newly formed rectangle = 112 inches
To Find:
Dimensions of the original rectangle = ?
Solution:
The perimeter rectangle
=> 2(L+B) =76 inches -----------------------(1)
If two of the boxes are placed next to each other on the long side the new box is a rectangle shape is formed
Then the perimeter of the new rectangle box will be
=> 2(L+B) + 2(L+B) - 2L = 112--------------------(2)
Substituting (1) in(2)
=> 76+ 76 - 2L = 112
=>156 -2L =112
=>2L = 156 -112
=> 2L = 40
=> L= [tex]\frac{40}{2}[/tex]
=>L = 20
Substituting L =20 in eq(1)
=> 2(20+B) =76
=> (40 +2B) = 76
=>2B = 76-40
=> 2B =36
=> B = [tex]\frac {36}{2}[/tex]
=> B = 18
