Answer:
Explanation:
mass of ethanol (s)[tex]m=49.4\ gm[/tex]
molar specific heat of fusion [tex]\Delta H_f=4.6\ KJ/mol[/tex]
molar specific heat of vaporization [tex]\Delta H_v=38.56\ KJ/mol[/tex]
specific heat of liquid [tex]c_l=2.45\ J/g-^{\circ}C[/tex]
specific heat of gas [tex]c_v=1.43\ J/g-^{\circ}C[/tex]
no of moles of ethanol [tex]n=\frac{49.4}{46}=1.074\ mol[/tex]
[tex]Q_1=n\times \Delta H_f=1.074\times 4.6=4.94\ KJ[/tex]
[tex]Q_2=mc_l\Delta T=49.4\times 2.45\times (192.9)[/tex]
[tex]Q_2=23.346\ KJ[/tex]
[tex]Q_3=n\times \Delta H_v=1.074\times 38.56=41.41\ KJ[/tex]
[tex]Q_4=mc_v\Delta T=49.4\times 1.43\times (192.9)=13.626\ KJ[/tex]
[tex]Q_{net}=Q_1+Q_2+Q_3+Q_4[/tex]
[tex]Q_{net}=83.322\ KJ[/tex]
