Answer:
option A
Explanation:
given,
Kinetic energy of the car = 2000 J
speed of the car is doubled
we know,
[tex]KE_1 = \dfrac{1}{2}mv^2[/tex]
[tex]2000= \dfrac{1}{2}mv^2[/tex]........(1)
now, speed of the car is doubled
v' = 2 v
[tex]KE_2 = \dfrac{1}{2}mv'^2[/tex]
[tex]KE_2 = \dfrac{1}{2}m(2v)^2[/tex]
from equation (1)
[tex]KE_2 = 4\times \dfrac{1}{2}m(v)^2[/tex]
[tex]KE_2 = 4\times 2000[/tex]
[tex]KE_2 = 8000\ J[/tex]
Hence, the Kinetic energy would be equal to 8000 J.
The correct answer is option A.
