The solution of system of equations is: x = 1.6 and y = 1.2
Step-by-step explanation:
Given equations are:
[tex]y = 2-\frac{1}{2}x\ \ \ \ Eqn\ 1\\x-3y = -2\ \ \ eqn\ 2[/tex]
Putting [tex]y = 2-\frac{1}{2}x[/tex] in equation 2
[tex]x - 3(2-\frac{1}{2}x) = -2\\x - 6 + \frac{3}{2}x = -2\\x +\frac{3}{2}x = -2+6\\\frac{2x+3x}{2} = 4\\\frac{5x}{2} = 4\\5x = 4 * 2\\5x = 8\\x = \frac{8}{5}\\x = 1.6[/tex]
Putting x = 1.6 in equation 2
[tex]1.6-3y = -2\\-3y = -2-1.6\\-3y =- 3.6[/tex]
Dividing both sides by -3
[tex]\frac{-3y}{-3} = \frac{-3.6}{-3}\\y = 1.2[/tex]
Hence,
The solution of system of equations is: x = 1.6 and y = 1.2
Keywords: Linear equations, variables
Learn more about linear equations at:
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