a) The net force is zero
b) The force applied is 4.9 N
Explanation:
a)
We can solve this first part of the problem by applying Newton's second law, which states that the net force applied to an object is equal to the product between the mass of the object and its acceleration:
[tex]\sum F = ma[/tex] (1)
where
[tex]\sum F[/tex] is the net force
m is the mass of the object
a is its acceleration
In this problem, we are told that the box is moving at a constant speed of 4.00 m/s. Constant speed means that the acceleration of the box is zero:
a = 0
Therefore, the equation (1) becomes
[tex]\sum F = 0[/tex]
which means that the net force on the box is zero.
b)
There is a missing piece of information in this part: the mass of the box. I will assume it is 1 kg.
To solve this part, we have to analyze the forces acting along the direction parallel to the slope.
We have two forces acting in this direction:
- The applied force, F, pushing forward along the slope
- The component of the weight parallel to the slope, [tex]mg sin \theta[/tex], pulling down along the slope
Since the net force is zero, the equation of motion along this direction becomes:
[tex]F - mg sin \theta = 0[/tex]
where
m = 1 kg is the mass of the box
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
[tex]\theta=30.0^{\circ}[/tex] is the angle of the ramp
And solving for F, we find the force applied:
[tex]F=mg sin \theta = (1)(9.8)(sin 30.0^{\circ})=4.9 N[/tex]
Learn more about Newton's second law:
brainly.com/question/3820012
Learn more about slopes:
brainly.com/question/5884009
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