During two years, the population of birds of an island became 7 times more than before. If the first year increase in the population was 40% , what was the percent increase of the second year?

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Answer:

The percent increase of the second year is 400%.

Step-by-step explanation:

Consider the provided information.

Let the population of birds was x.

After 2 years the population becomes 7 times more than before.

Therefore, after 2 years population is 7x.

In first year increase in the population was 40%.

Population after 1st year = x + 40% of x

Population after 1st year = x + 0.40x

Population after 1st year = 1.4x

The population increase from 1st year to 2nd year is: 7x-1.4x=5.6x

Thus the percentage increase is:

[tex]\% increase=\frac{5.6x}{1.4x}\times100=400\%[/tex]

Hence, in second year the population of birds increase by 400%.

The percent increase of the second year is 4% and this can be determined by forming the linear equation.

Given :

  • During two years, the population of birds on an island became 7 times more than before.
  • The first-year increase in the population was 40%.

Let the total population of birds be 'a'. Then after two years, the population of birds on an island becomes 7a.

In the first year if the increase in population is 40% then population after first year = a + 0.4a = 1.4a

After the second year increase in population = 7a - 1.4a = 5.6a

The percentage increase is given by:

[tex]% increase = \dfrac{5.6x}{1.4x}=4[/tex][tex]\dfrac{5.6a}{1.4a}=4[/tex]

The percentage increase is 4%.

For more information, refer to the link given below:

https://brainly.com/question/2263981