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4. The regression line for this bivariate data set is = 19.41 + .17x. What is the residual for the point with an x-value of 68? x 56 45 68 49 58 63 66 62 y 28 25 34 30 32 36 23 29

Respuesta :

Answer:

3.03

Step-by-step explanation:

x y

 

56 28

45 25

68 34

49 30

58 32

63 36

66 23

62 29

 

slope 0.174993175

Intercept 19.40977341

[tex]y=19.41+0.17x[/tex]

is the regression line

As per line, we can find y for x=68 as

[tex]y(68) = 19.41+0.17(68)\\= 30.97[/tex]

For x=68

y actual = 34

y predicted = 30.97

Residual = 34-30.97

= 3.03

Answer:

i don't know

Step-by-step explanation:

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