Answer:
Option B. is the answer.
Step-by-step explanation:
The given question is incomplete; complete question has been given in the picture attached.
Current in the circuit at the time t is [tex]I_{0}sinwt[/tex].
Power delivered to the resistor is [tex]I_{0}Rsin^{2}wt[/tex]
Where R = resistance
We have to express the power in the terms of cos2w.
Since formula to get the power in a circuit with resistance R and current I is given by
P = I²R
Therefore, power for the given circuit will be
P = [tex](I_{0})^{2} Rsin^{2}wt[/tex]
P = [tex]I^{2}_{0}R(\frac{1-cos2wt}{2})[/tex] [Since sin²t = [tex]\frac{1-sin^{2}wt}{2}[/tex]]
P = [tex]\frac{I^{2}_{0}R}{2}-\frac{1}{2}I^{2}_{0}cos2wt[/tex]
Therefore, Option B. will be the answer.
Answer:
B on Edge
Step-by-step explanation:
Got it right on the test
