Acceleration in the east direction: [tex]-4.2 m/s^2[/tex]
Acceleration in the north direction: [tex]9.1 m/s^2[/tex]
Explanation:
In order to find the acceleration of the car in the north and east direction, we need to resolve the acceleration vector into its components along the north and east direction.
Taking east as positive x-direction and north as positive y-direction, the two components of the vector are given by:
[tex]a_x = a cos \theta[/tex]
[tex]a_y = a sin \theta[/tex]
where
[tex]a=10 m/s^2[/tex] is the magnitude of the acceleration
[tex]\theta=180^{\circ}-65^{\circ}=115^{\circ}[/tex] is the angle with the positive x-axis
Substituting, we find the components of the acceleration:
[tex]a_x = (10)(cos 115^{\circ})=-4.2 m/s^2[/tex]
[tex]a_y = (10)(sin 115^{\circ})=9.1 m/s^2[/tex]
Learn more about vector components:
brainly.com/question/2678571
#LearnwithBrainly
