Respuesta :

Answer:

If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)

Explanation:

Step 1: Data given

Number of moles iron (III) oxide (Fe2O3) = 0.66 moles

Step 2: The balanced equation

4Fe + 3O2 → 2Fe2O3

Step 3: Calculate moles of oxygen (O2)

For 4 moles Fe consumed, we need 3 moles of O2 to produce 2 moles of Fe2O3

For 0.66 moles Fe2O3 produced, we need 3/2 * 0.66 = 0.99 moles of O2

If there is 0.66 moles of iron(III)oxide produced, there reacte 0.99 moles of oxygen (O2)

dsdrajlin

Answer:

0.99 moles of O₂

Explanation:

Let's consider the reaction between iron and oxygen to produce iron (III) oxide.

4 Fe + 3 O₂ → 2 Fe₂O₃

The molar ratio of oxygen to iron (III) oxide is 3:2. The moles of oxygen that reacted to form 0.66 moles of iron (III) oxide are:

0.66 mol Fe₂O₃ × (3 mol O₂/2 mol Fe₂O₃) = 0.99 mol O₂

0.99 moles of O₂ reacted to produce 0.66 moles of Fe₂O₃.

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