Answer:
[tex]$ \frac{8}{3xy^2} $[/tex]
Step-by-step explanation:
Given:
[tex]$ \frac{8y^3}{3xy^5} $[/tex]
We have: [tex]$ \frac{a^b}{a^c} = a^{b - c} $[/tex]
Therefore, [tex]$ \frac{8y^3}{3xy^5} = \frac{8}{3}x^{-1}y^{3 - 5} $[/tex]
[tex]$ = \frac{8}{3xy^2} $[/tex]
This is the answer.
