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Answer:

2 mol of Al₂O₃ are produced from 6 mol of FeO

Explanation:

The reaction to produce aluminum oxide from FeO is this:

3FeO  +  2Al  → 3Fe  + Al₂O₃

Ratio is 3:1

3 mol of FeO are necessary to produce 1 mol of aluminum oxide

6 mol of FeO will produce (6 .1)/3 = 2 moles

Answer:

There are 2.0 moles of Al2O3 produced

Explanation:

Step 1: Data given

Number of moles of FeO = 6.0 moles

Step 2: The balanced equation

2Al + 3FeO → Al2O3 + 3Fe

Step 3: Calculate moles of Al2O3

When 2 moles of Al are consumed, we need 3 moles of FeO to produce 1 mol of Al2O3 and 3 moles of Fe

When 6 moles of FeO are consumed, we'll have 6.0 / 3 = 2.0 moles of Al2O3

There are 2.0 moles of Al2O3 produced

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