A new fountain in the shape of a hexagon will have 6 sides of equal length. On a scale drawing, the coordinates of the vertices of the fountain are: (7.5,5), (11.5,2), (7.5,−1), (2.5,−1), (−1.5,2), and (2.5,5).

How long is each side of the fountain?


Respuesta :

Answer:

Each side of the fountain is 5 units

Step-by-step explanation:

Given:

All the sides of the vertices are equal.

Vertices of the fountain

(7.5,5),

(11.5,2),

(7.5,−1),

(2.5,−1),

(−1.5,2),

(2.5,5)

To Find:

Length of the each side of the fountain = ?

Solution:

Let us find the Length of the hexagon using the distance formula

Distance formula = [tex]\sqrt{(x_2-x_1)^2 +(y_2-y_2)^2}[/tex]

Now lets find the length of AB

Length of AB = [tex]\sqrt{(x_2-x_1)^2 +(y_2-y_2)^2}[/tex]

where

[tex]x_1[/tex] = 7.5

[tex]x_2[/tex] = 11.5

[tex]y_1[/tex] = 5

[tex]y_2[/tex] = 2

Substituting the values we get,

Length of AB = [tex]\sqrt{(11.5 - 7.5)^2 +(5-2)^2}[/tex]

Length of AB = [tex]\sqrt{(4)^2 +(3)^2}[/tex]

Length of AB = [tex]\sqrt{16 +9}[/tex]

Length of AB = [tex]\sqrt{25}[/tex]

Length of AB = 5

Since all the sides of the hexagon are said to be equal, the length of the sides of the hexagon is 5 units

Answer:

5 units

Step-by-step explanation: