If the circuit is capacitive reactance measured 650 Ω and its resistance measures 1,200 Ω, what is the phase angle between circuit voltage and current?

Respuesta :

Answer:

[tex]\phi=28.4^{\circ}[/tex]

Explanation:

We are given that

Capacitive reactance=[tex]X_c=650\Omega[/tex]

Resistance of circuit= R=[tex]1200\Omega[/tex]

We have to find the phase angle between circuit voltage and current.

We know that

Phase angle, [tex]\phi=tan^{-1}(\frac{X_c}{R})[/tex]

By using this formula we will find the phase angle between voltage and current of circuit.

Substitute the values then we get

[tex]\phi=\tan^{-1}(\frac{650}{1200})[/tex]

[tex]\phi=\tan^{-1}(0.54)[/tex]

[tex]\phi=28.4^{\circ}[/tex]

Hence, the phase angle between circuit voltage and current=28.4 degrees