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During two years, the population of birds of an island became 7 times more than before. If the first year increase in the population was 40% , what was the percent increase of the second year?

Respuesta :

lucic

The percent increase of the second year was 85.71%

Step-by-step explanation:

The exponential growth formula is y=a(1+r)^x

where;

y=population after x years

a=original population

r=growth rate as a decimal

x=number of time interval that have passed

Let starting population be p

The first year increase in the population was 40% this means;

r=0.4 , x=1 and a=p thus the equation will be

y=p(1+0.4)^1 ⇒⇒y=1.4 p

In the second year the population of birds of an island became 7 times more than before which is 7p

7p= 7*1.4p= 9.8p

Increase will be;

9.8p-1.4p=8.4

% increase will be;

8.4/9.8 *100 =85.71%

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twinklingrubies

Answer:

The percent increase of the second year is 400%.

Step-by-step explanation:

Consider the provided information.

Let the population of birds was x.

After 2 years the population becomes 7 times more than before.

Therefore, after 2 years population is 7x.

In first year increase in the population was 40%.

Population after 1st year = x + 40% of x

Population after 1st year = x + 0.40x

Population after 1st year = 1.4x

The population increase from 1st year to 2nd year is: 7x-1.4x=5.6x

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