a) The acceleration of the car is [tex]0.33 m/s^2[/tex]
b) The new acceleration would be[tex]0.17 m/s^2[/tex]
Explanation:
a)
The acceleration of a body is equal to the rate of change of the velocity:
[tex]a=\frac{\Delta v}{\Delta t}[/tex]
where
[tex]\Delta v[/tex] is the change in velocity
[tex]\Delta t[/tex] is the time interval considered
For the data of the car in this problem, we have:
[tex]v_1 = 0.13 m/s[/tex] is the initial velocity
[tex]v_2 = 0.36 m/s[/tex] is the final velocity
[tex]t_1 = 1.92 s[/tex] is the initial time
[tex]t_2 = 2.61 s[/tex] is the final time
Substituting, we find the acceleration:
[tex]a=\frac{v_2-v_1}{t_2-t_1}=\frac{0.36-0.13}{2.61-1.92}=0.33 m/s^2[/tex]
b)
To solve this part, we can apply Newton's second law of motion, which states that the net force applied on a body is equal to the product between its mass and its acceleration:
[tex]F=ma[/tex]
where
F is the net force
m is the mass
a is the acceleration
The equation can be rewritten as
[tex]a=\frac{F}{m}[/tex]
We observe that the acceleration is directly proportional to the force: therefore, if the force were cut in half, the acceleration will also halve. Therefore, the new acceleration would be
[tex]a' = \frac{a}{2}=\frac{0.33}{2}=0.17 m/s^2[/tex]
Learn more about force and acceleration:
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