Respuesta :
Answer:
82g
Explanation:
CaCl2 : Ca 111g : 40g
227.45 : xg
xg= (40×227.5)/111
Answer:
[tex]m_{Ca}=99.982gCa[/tex]
Explanation:
Hello, in this case, considering that the undergoing chemical reaction is:
[tex]CaCl_2(l) \rightarrow Ca(s) + Cl_2(g)[/tex]
As we see a one-to-one molar relationship between calcium chloride and calcium, by stoichiometry and the given molar masses, the mass of calcium that would be formed is:
[tex]m_{Ca}=277.45gCaCl_2*\frac{1molCaCl_2}{111gCaCl_2} *\frac{1molCa}{1molCaCl_2} *\frac{40gCa}{1molCa} \\m_{Ca}=99.982gCa[/tex]
Best regards.