A 90.0kg person stands 1.25m from a 60.0kg person sitting on a bench nearby. What is the magnitude of the gravitational force between them ?

Respuesta :

Answer: [tex]23(10)^{-8} N[/tex]

Explanation:

According to Newton's law of Gravitation, the force [tex]F[/tex] exerted between two bodies of masses [tex]m1[/tex] and [tex]m2[/tex]  and separated by a distance [tex]r[/tex]  is equal to the product of their masses and inversely proportional to the square of the distance:

[tex]F=G\frac{(m1)(m2)}{r^2}[/tex] (1)

Where:

[tex]G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}[/tex] is the Gravitational Constant

[tex]m1=90 kg[/tex] is the mass of the first person

[tex]m2=60 kg[/tex] is the mass of the second person

[tex]r=1.25 m[/tex]  is the distance between both persons

Solving:

[tex]F=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(90 kg)(60 kg)}{(1.25 m)^2}[/tex] (2)

Finally:

[tex]F=23(10)^{-8} N[/tex]  This is the gravitational force between both persons. As you can see is too small.