The gravitational force between the students is [tex]3.2\cdot 10^{-8}N[/tex]
Explanation:
The magnitude of the gravitational force between two objects is given by :
[tex]F=G\frac{m_1 m_2}{r^2}[/tex]
where
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant
[tex]m_1, m_2[/tex] are the masses of the two objects
r is the separation between them
In this problem, we have:
[tex]m_1 = 60.0 kg[/tex] is the mass of the first student
[tex]m_2 = 50.0 kg[/tex] is the mass of the second student
r = 2.50 m is their separation
Substituting into the equation, we find the gravitational force between the students:
[tex]F=\frac{(6.67\cdot 10^{-11})(60.0)(50.0)}{(2.50)^2}=3.2\cdot 10^{-8}N[/tex]
Learn more about gravitational force:
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