Answer:5041.90 m/s
Explanation:
The escape velocity equation is:
[tex]V_{e}=\sqrt{\frac{2GM}{R}}[/tex] (1)
Where:
[tex]V_{e}[/tex] is the escape velocity
[tex]G=6.67(10)^{-11} Nm^{2}/kg^{2}[/tex] is the Universal Gravitational constant
[tex]M=6.46(10)^{23}kg[/tex] is the mass of Mars
[tex]R=3.39(10)^{6} m[/tex] is Mar's radius
Solving:
[tex]V_{e}=\sqrt{\frac{2(6.67(10)^{-11} Nm^{2}/kg^{2})(6.46(10)^{23}kg)}{3.39(10)^{6} m}}[/tex] (2)
Finally:
[tex]V_{e}=5041.90 m/s[/tex] This is the escape velocity on Mars
