Answer:
74
Step-by-step explanation:
Given
[tex]a_{32}=\dfrac{389}{4}\\ \\d=\dfrac{3}{4}[/tex]
Use the formula for the [tex]n^{th}[/tex] term of arithmetic sequence:
[tex]a_n=a_1+(n-1)d[/tex]
For the [tex]a_{32},[/tex] you have that [tex]n=32,[/tex] so
[tex]a_{32}=a_1+(32-1)d\\ \\\dfrac{389}{4}=a_1+31\cdot \dfrac{3}{4}\\ \\\dfrac{389}{4}=a_1+\dfrac{93}{4}\\ \\a_1=\dfrac{389}{4}-\dfrac{93}{4}\\ \\a_1=\dfrac{296}{4}\\ \\a_1=74[/tex]
