20th term of sequence is 800
Solution:
Given sequence is 2, 8, 18, 32
To find: 20th term of sequence
Let us first find the pattern followed by sequence
[tex]2 \times 1 \times 1 = 2\\\\2 \times 2 \times 2 = 8\\\\2 \times 3 \times 3 = 18\\\\2 \times 4 \times 4 = 32[/tex]
So the next term is found by multiplying 2 with the square of location of term
For nth term, we can represent by
[tex]a_n = 2n^2[/tex]
Where, n = 1, 2, 3, .........
To find 20th term
n = 20
[tex]a_{20} = 2(20)^2 = 2 \times 400 = 800[/tex]
Thus 20th term of sequence is 800
