A person is standing on a cliff that is 200ft above a body of water. The person looks down at an angle of depression of 42o at a sailboat. Then the person looks at a yacht that is further out at an angle of depression of 15o. What is the distance (in feet) between the sailboat and the yacht?

Respuesta :

Answer:

524.5 feet

Step-by-step explanation:

Given: Height of cliff= 200 ft

           Angle of depression at sail boat is 42°

           Angle of depression at yacht is 15°

Lets assume distance sailboat from the bottom of cliff is "[tex]d_1[/tex]"

And assume distance yacht from the bottom of cliff is "[tex]d_2[/tex]"

Now using tangent rule to solve it.

we know, [tex]tan\theta = \frac{opposite}{adjacent}[/tex]

Distance sailboat from the bottom of cliff; [tex]tan 42= \frac{200}{d_1}[/tex]

Using trignometry table to know the value of tan 42°

⇒[tex]0.90= \frac{200}{d_1}[/tex]

cross multiplying both side.

⇒ [tex]d_1= \frac{200}{0.90} = 222.22 \approx 222[/tex]

Distance sailboat from the bottom of cliff ([tex]d_1)[/tex]= 222 feet

Distance yatch from the bottom of cliff; [tex]tan 15= \frac{200}{d_2}[/tex]

Using trignometry table to know the value of tan 15°

⇒[tex]0.2679= \frac{200}{d_2}[/tex]

cross multiplying both side.

⇒ [tex]d_2= \frac{200}{0.2679} = 746.54 \approx 746.5[/tex]

∴Distance yacht from the bottom of cliff [tex](d_2)[/tex]= 746.5 feet.

Next, finding the distance between sailboat and yacht.

Distance between sailboat and yacht = [tex]d_2-d_1[/tex]

⇒ Distance between sailboat and yacht= [tex]746.5-222= 524.5\ ft[/tex]

Distance between sailboat and yacht is 524.5 feet.