You are moving the robot to your classroom, which measures 30 feet by 40 feet.
1. Draw the classroom set up on a coordinate plane using (30,40) as the northeast vertex.
2. The robot was initially placed at position (6,9), and at tt = 2 seconds, its position is (10,15). a. How far did the robot travel in 2 seconds.
b. What is the speed of the robot?

Respuesta :

Answer:

1) See figure attached

2)

a) [tex] d = \sqrt{(x_2 -x_1)^2 +(y_2 -y_1)^2}[/tex]

And if we replace we got:

[tex] d = \sqrt{(10 -6)^2 +(15 -9)^2}= 7.211[/tex]

b) [tex] V = \frac{d}{t}[/tex]

And if we replace we got:

[tex] V = \frac{7.211 ft}{2 sec}=3.606 s[/tex]

Step-by-step explanation:

Part 1

We can see the plot in the figure attached.

Part 2

a)

For this case we have two points [tex] (x_1 , y_1) = (6,9) , (x_2 , y_2) = (10,15)[/tex]

And we want to find the distance travelled between these two points and we can use the following formula from the euclidian distance between two points:

[tex] d = \sqrt{(x_2 -x_1)^2 +(y_2 -y_1)^2}[/tex]

And if we replace we got:

[tex] d = \sqrt{(10 -6)^2 +(15 -9)^2}= 7.211[/tex]

b)

Since it takes two seconds in order to go from (6.9) to (10,15) we can use the definition of velocity:

[tex] V = \frac{d}{t}[/tex]

And if we replace we got:

[tex] V = \frac{7.211 ft}{2 sec}=3.606 s[/tex]

Ver imagen dfbustos