Answer:
Electric field will be [tex]1.5\times 10^{6}V/m[/tex]
Explanation:
We have given potential difference between the two plates = 15000 volt
Distance between the plates = [tex]d=1cm=10^{-2}m[/tex]
We have to find the electric field strength between the plates
Potential difference between the plates is equal to [tex]V=Ed[/tex]
So electric field strength will be [tex]E=\frac{V}{d}=\frac{15000}{10^{-2}}=1.5\times 10^{6}V/m[/tex]
So electric field will be [tex]1.5\times 10^{6}V/m[/tex]
