Answer:
[tex] A(square) = x*x= x^2 [/tex]
[tex] A(rectangle) = (a-2) (a+2) = a^2 +2a- 2a-4 = a^2 -4[/tex]
[tex] A(rectangle) = A(square) -4[/tex]
Step-by-step explanation:
For this case we assume that the square have sides of length x.
So then the area for this square is given by [tex] A(square) = x*x= x^2 [/tex]
We have a rectangle and on this case we have this information :" the rectangle has side lengths 2 less and 2 more than a square"
So then the sides of the rectangle needs to have lengths a-2 and a+2, and if we find the area for the rectangle we got:
[tex] A(rectangle) = (a-2) (a+2) = a^2 +2a- 2a-4 = a^2 -4[/tex]
And as we can see th area for the rectangl is 4 units less than the area for the rectangle:
[tex] A(rectangle) = A(square) -4[/tex]
