Answer:
(A) [tex]\frac{\pi }{3}[/tex]
(b) [tex]1.768\pi[/tex]
Step-by-step explanation:
It is given in the question that [tex]0\leq x\leq 2\pi[/tex]
(a) We have given equation [tex]2cosx-1=0[/tex]
[tex]cosx=\frac{1}{2}[/tex]
[tex]x=cos^{-1}\frac{1}{2}[/tex]
[tex]x=\frac{\pi }{3}[/tex]
(b) [tex]3sinx+2=0[/tex]
[tex]sinx=\frac{-2}{3}[/tex]
[tex]x=sin^{-1}(-0.666)[/tex]
[tex]x=-41.75^{\circ}=360-41.75=318.25^{\circ}=1.768\pi[/tex]
