Problem 1: Two charged balloons of +2.30 x 10-10 coulombs each are placed 3.20 x 10 meters apart. What is the
magnitude of the force of interaction between the two balloons? (k = 9.0 x 10° newtonmeters /coulomb)
Part Brothe r

Respuesta :

The electrostatic force between the two balloons is [tex]4.6\cdot 10^{-13} N[/tex]

Explanation:

The magnitude of the electrostatic force between two charged objects is given by Coulomb's law:

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where:

[tex]k=8.99\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant

[tex]q_1, q_2[/tex] are the two charges

r is the separation between the two charges

In this problem, we have two charged balloons, with charges of:

[tex]q_1 = +2.30 \cdot 10^{-10}C\\q_2 = +2.30\cdot 10^{-10}C[/tex]

While their separation is

[tex]r=3.20\cdot 10 m = 32.0 m[/tex]

Substituting into the equation, we find the force between the two balloons:

[tex]F=(8.99\cdot 10^9)\frac{(2.30\cdot 10^{-10})^2}{(32.0)^2}=4.6\cdot 10^{-13} N[/tex]

Moreover, since the two ballons are both positively charged, the force between them is repulsive.

Learn more about electric force:

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