Answer:
1) one real solution
2) no real solution
3) two real solutions
4) no real solution
Step-by-step explanation:
We have to determine the number of real solutions for each quadratic equation without solving.
[tex]ax^2 + bx +c=0\\D = b^2-4ac\\\text{If D is positive there are two real solutions}\\\text{Pif D is zero then there is one real solution}\\\text{if D is negative then there are no real solution.}[/tex]
1)
[tex]p^2 + 7p + 33 = 8 - 3p\\p^2+10p+25=0\\D = 10^2 - 4(1)(25) = 0[/tex]
Thus, the quadratic equation has one real solution.
2)
[tex]7x^2 + 2x + 5 = 0\\D = 2^2 - 4(7)(5) < 0[/tex]
Thus, the quadratic equation has no real solution.
3)
[tex]2y^2 + 10y = y^2 + 4y - 3\\y^2+6y+3=0\\D = 6^2 - 4(1)(3) > 0[/tex]
Thus, the quadratic equation has two real solutions.
4)
[tex]4z^2 + 9 = -4z\\4z^2 + 4z + 9 = 0\\D =4^2 - 4(4)(9) < 0[/tex]
Thus, the quadratic equation has no real solution.
