Answer:
(a) [tex]x=\sqrt{3}[/tex]
(b) [tex]y=\frac{1}{2}[/tex]
(c) Answer of part a is equation of line [tex]x=\sqrt{3}[/tex] which is parallel to y axis and in part by equation of line is [tex]y=\frac{1}{2}[/tex] which is parallel to x axis
Step-by-step explanation:
We have given points are [tex](\sqrt{3},\frac{1}{2})[/tex]
(a) Equation of line is given x = -9
We have to find the equation of line parallel to x= -9 and passing through [tex](\sqrt{3},\frac{1}{2})[/tex]
x = -9 line is parallel to y axis and so slope will be infinite
Equation of line is given by [tex]y-y_1=m(x-x_1)[/tex]
So [tex]y-\frac{1}{2}=\frac{1}{0}(x-\sqrt{3})[/tex]
[tex]x=\sqrt{3}[/tex]
(b) Equation of line is given [tex]y=-\sqrt{7}[/tex]
This line is parallel to x axis so slope will be zero
So equation of line will be [tex]y-\frac{1}{2}=0(x-\sqrt{3})[/tex]
[tex]y=\frac{1}{2}[/tex]
(c) Answer of part a is equation of line [tex]x=\sqrt{3}[/tex] which is parallel to y axis and in part by equation of line is [tex]y=\frac{1}{2}[/tex] which is parallel to x axis
