Answer:
The answer to your question is (d + 2)(3d - 5)
Step-by-step explanation:
3d² + d - 10
Multiply the first term (3) by the third (-10) = 3 x -10 = -30
Find the prime factors of -30
-30 2
-15 3
-5 5
1
Then, -30 = 2 x 3 x 5
Find two numbers that added gives +1 and multiply gives -30. These numbers are 6 (2 x 3) and -5
Write the mid term as the addition of the numbers got.
1d = 6d - 5d
Write the polynomial as these terms
3d² + 6d - 5d - 10
Factor by grouping 3d(d + 2) - 5(d - 2)
Factor by grouping again (d + 2)(3d - 5)
Now, the polynomial is factor completely.
