A pilot is flying over a straight highway. He determines
theangles of depression to two miles posts, 5 miles apart, to
be32o and 48o.
a.) Find the distance of the plane from point A
b.) Find the elevation of the plane.

Respuesta :

Answer:

a) 3.77 miles

b) 2 miles

Step-by-step explanation:

Law of Sines:

[tex]\frac{a}{sin(A)} =\frac{b}{sin(B)}[/tex]

a) The distance of the plane from point A

The angle of depression corresponds to the congruent angle of elevation therefore, 180-28-52 = 100°

[tex]\frac{5}{sin(100)} =\frac{b}{sin(48)}[/tex]

[tex]b=\frac{5sin(48)}{sin(100)}[/tex]

[tex]b≅3.77[/tex]  miles

b) Elevation of the plane

[tex]sin=\frac{opposite}{hypotenuse}[/tex]

hypotenuse is 3.77 and opposite is the elevation(h) to be found

[tex]sin(32)=\frac{h}{3.77}[/tex]

[tex]h=sin(32) 3.77[/tex]

[tex]h≅2[/tex]

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