Answer:
The force is 679.73 ft-lb = 921.59J.
Step-by-step explanation:
The work is given by the following formula:
[tex]W = F*d*\cos{\alpha}[/tex]
In which F is the force applied, d is the distance, and [tex]\alpha[/tex] is the angle at which the force is applied.
In this problem, we have that:
[tex]F = 15, d = 50, \alpha = 25[/tex]
So
[tex]W = F*d*\cos{\alpha} = 15*50*\cos{25} = 679.73[/tex] ft-lb.
Each ft-lb has 1.356J. So the force is 679.73 ft-lb = 921.59J.
The work done is 679.7 lb*ft.
Work is defined as the dot product between force and distance moved. Because the package moves horizontally, then we need to find the horizontal component of the force.
We know that the force is F, it has a magnitude of 15 lb and with an angle of 25° with the horizontal. Then the horizontal component will be given by:
f = (15lb)*cos(25°) = 13.59 lb
And the package is pushed for 50ft, then the work is:
W = (13.59 lb)*(50 ft) = 679.73 lb*ft
If you want to learn more about work, you can read:
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